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1) If log 0.317=0.3332 and log 0.318=0.3364 then
find log 0.319 =
Sol: Given log 0.317=0.3332 and log 0.318=0.3364
Then
Log 0.319=log0.318+ (log0.318-log0.317)
=0.3396
2) A box of 150 packets consists of 1kg
packets and 2kg packets. Total weight of box is 264kg. How many 2kg
packets are there?
Sol: Given x= 2 kg Packs
y= 1 kg packs
=> x + y = 150 .......... Eqn 1
=> 2x + y = 264 .......... Eqn 2
On solving these two equations
x = 114
By using equation 1
114 + y = 150
=> y = 36
=>Number of 2 kg Packs = 114.
3) My flight takes of at 2am from a place at 18N
10E and landed 10 Hrs later at a place with coordinates 36N70W. What is
the local time when my plane landed?
a) 6:00 am b) 6:40am c) 7:40 d) 7:00 e) 8:00
Sol: (Hint: Every 1 deg longitude is equal to 4
minutes. If west to east add time else subtract time)
Ans: 8:00
4) A Flight takes off at 2 A.M from northeast
direction and travels for 11 hours to reach the destination, which is
in northwest direction. Given the latitude and longitude of source and
destination. Find the local time of destination when the flight reaches
there?
Ans: 7 AM (or) 1 PM
5) A moves 3 kms east from his starting point. He
then travels 5 kms north. From that point he moves 8 kms to the east.
How far is A from his starting point?
Ans: 13 kms
6) Aeroplane is flying at a particular angle and
latitude, after some time latitude is given. (8 hrs later), u r asked
to find the local time of the place.
7) An Aeroplane starts from A (SOME LATITUDE IS
GIVEN ACCORDING TO PLACE).At 2 AM local time to B (SOME LATITUDE).
Traveling time is 10 Hours. What is the local time of B when it reaches
B?
8) A plane moves from
9°N40°E to
9°N40°W. If the plane starts at
10 am and takes 8 hours to reach the destination, find the local
arrival time.
Sol: Since it is moving from east to west
longitude we need to add both
Ie, 40+40=80
Multiply the ans by 4
=>80*4=320min
Convert this min to hours i.e., 5hrs 33min
It takes 8hrs totally. So 8-5hr 30 min=2hr 30min
So the ans is 10am+2hr 30 min
Ans: 12:30 it will reach
9) The size of the bucket is N kb. The bucket
fills at the rate of 0.1 kb per millisecond. A programmer sends a
program to receiver. There it waits for 10 milliseconds. And response
will be back to programmer in 20 milliseconds. How much time the
program takes to get a response back to the programmer, after it is
sent?
Sol: The time being taken to fill the bucket.
After reaching program it waits there for 10ms
and back to the programmer in
20 ms. then total time to get the response is
20ms +10 ms=30ms
Ans: 30ms
10) A file is transferred from one location to
another in
‘buckets’.
The size of the bucket is 10 kilobytes. Eh bucket gets filled at the
rate of 0.0001 kilobytes per millisecond. The transmission time from
sender to receiver is 10 milliseconds per bucket. After the receipt of
the bucket the receiver sends an acknowledgement that reaches sender in
100 milliseconds. Assuming no error during transmission, write a
formula to calculate the time taken in seconds to successfully complete
the transfer of a file of size N kilobytes.
Ans: (n/1000)*(n/10)*10+ (n/100).... (Not 100%
sure)
11)A fisherman's day is rated as good if he
catches 9 fishes ,fair if 7 fishes and bad if 5 fishes .He catches 53
fishes in a week n had all good, fair n bad days in the week. So how
many good, fair n bad days did the fisher man had in the week.
Sol:
good days means --- 9 fishes so
53/9=4(remainder=17) if u assume 5 then there is no chance for bad days.
fair days means ----- 7 fishes so remaining 17 ---
17/7=1(remainder=10) if u assume 2 then there is no chance for bad days.
bad days means -------5 fishes so remaining
10---10/5=2days.
4*9=36
7*1=7
2*5=10
36+7+10=53...
Ans: 4 good, 1 fair, 2bad. ==== total 7 days.
12) x+y+z=7--------- eq1
9*x+7*y+5*z=53 -------eq2
Sol:
Multiply eq 1 by 9,
9*x+9*y+9*z=35 -------------eq3
From eq2 and eq3
2*y+4*z=10-----eq4
Since all x, y and z are integer i should put a
integer value of y such that z sud be integer in eq 4.....And there
will be two value y=1 or 3 then z = 2 or 1 from eq 4
For first y=1,z=2 then from eq1 x= 4
So 9*4+1*7+2*5=53.... Satisfied
Now for second y=3 z=1 then from eq1 x=3
So 9*3+3*7+1*5=53 ......satisfied
So finally there are two solution of this question
Ans:(x,y,z)=(4,1,2) and (3,3,1)...
13) Y catches 5 times more fishes than X. If total
number of fishes caught by X and Y is 42, then number of fishes caught
by X?
Sol: let no. of fish x catches=p
No. caught by y =r
r=5p.
Given r+p=42
Then p=7, r=35
14) Three companies are working independently and
receiving the savings 20%, 30%, 40%. If the companies work combine,
what will be their net savings?
Sol: Suppose total income is 100
So amount x is getting is 80
y is 70
z =60
Total=210
But total money is 300
300-210=90
So they are getting 90 rs less
90 is 30% of 300 so they r getting 30% discount
15) The ratio of incomes of C and D is 3:4.the
ratio of their expenditures is 4:5.Find the ratio of their savings if
the savings of C is one fourths of his income?
Sol: incomes: 3:4
Expenditures: 4:5
3x-4y=1/4(3x)
12x-16y=3x
9x=16y
y=9x/16
(3x-4(9x/16))/ ((4x-5(9x/16)))
Ans: 12/19
16)If A can copy 50 pages in 10 hours and A and B
together can copy 70 pages in 10 hours, how much time does B takes to
copy 26 pages?
Sol: A can copy 50 pages in 10 hrs.
=>A can copy 5 pages in 1hr. (50/10)
Now A & B can copy 70 pages in 10hrs.
Thus, B can copy 90 pages in 10 hrs. [Eqn. is
(50+x)/2=70, where x--> no. of pages B can copy in 10 hrs.]
So, B can copy 9 pages in 1hr.
Therefore, to copy 26 pages B will need almost
3hrs.
Since in 3hrs B can copy 27 pages
17) A can copy 50 papers in 10 hours while both A
& B can copy 70 papers in 10 hours. Then for how many hours
required for B to copy 26 papers?
ANS: 13
18) A is twice efficient than B. A and B can both
work together to complete a work in 7 days. Then find in how many days
A alone can complete the work?
ANS: 10.5 (11)
19) A finish the work in 10 days. B is 60%
efficient than A. So how days does B take to finish the work?
Ans: 100/6 (4 days)
20) A finishes the work in 10 days & B in
8 days individually. If A works for only 6 days then how many days
should B work to complete A's work?
Ans: 3.2 days (4 days)
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